General Aptitude For Gate CSEIT – Set Theory Maxima-Minima Using Short Trick Method Part 1.
General Aptitude For Gate CSEIT – Set Theory Maxima-Minima Using Short Trick Method Part 1.
Contents [hide]
- 0.1 Set Theory – Maxima & Minima Short Tricks for GATE CSE/IT
- 0.2 1. Basic Formulas of Set Theory
- 0.3 2. Maxima and Minima Tricks in Set Theory
- 0.4 3. Shortcut Example Question
- 0.5 Question:
- 0.6 Solution:
- 0.7 4. Short Tricks to Remember
- 0.8 Conclusion
- 0.9 General Aptitude For Gate CSEIT – Set Theory Maxima-Minima Using Short Trick Method Part 1.
- 0.10 GATE Mechanical Resource
- 1
General Aptitude for GATE CSE/IT
- 1.1 Set Theory + Maxima-Minima Using Short Trick – Part 1
- 1.2
Part A: Set Theory – GATE-Oriented Concepts
- 1.3
Part B: Maxima & Minima (Short Trick Method)
- 1.4
GATE Tip:
- 1.5
Want More?
- 1.6 General Aptitude For Gate CSEIT – Set Theory Maxima-Minima Using Short Trick Method Part 1.
- 1.7 QUALITATIVE APTITUDE TRICKS & SHORTCUTS FOR
- 1.8 General-GATE-Aptitude-Book.pdf
- 1.9 Maxima and minima
Set Theory – Maxima & Minima Short Tricks for GATE CSE/IT
Set Theory is an important topic in GATE Computer Science & IT. Questions related to Maxima and Minima of sets often appear in Aptitude & Discrete Mathematics.
1. Basic Formulas of Set Theory
For two sets A and B:
Union Formula:
∣A∪B∣=∣A∣+∣B∣−∣A∩B∣|A \cup B| = |A| + |B| – |A \cap B|
Intersection Formula:
∣A∩B∣=∣A∣+∣B∣−∣A∪B∣|A \cap B| = |A| + |B| – |A \cup B|
Complement Formula:
∣Ac∣=U−∣A∣|A^c| = U – |A|
(where U is the universal set)
For Three Sets (A, B, C):
∣A∪B∪C∣=∣A∣+∣B∣+∣C∣−∣A∩B∣−∣B∩C∣−∣C∩A∣+∣A∩B∩C∣|A \cup B \cup C| = |A| + |B| + |C| – |A \cap B| – |B \cap C| – |C \cap A| + |A \cap B \cap C|
2. Maxima and Minima Tricks in Set Theory
Case 1: Finding Maximum Value of |A ∩ B|
The maximum value of |A ∩ B| occurs when one set is completely inside the other.
max(∣A∩B∣)=min(∣A∣,∣B∣)\max(|A \cap B|) = \min(|A|, |B|)
Case 2: Finding Minimum Value of |A ∩ B|
The minimum value of |A ∩ B| occurs when both sets are disjoint.
min(∣A∩B∣)=0\min(|A \cap B|) = 0
Case 3: Finding Maximum Value of |A ∪ B|
The maximum value of |A ∪ B| occurs when the two sets have no common elements.
max(∣A∪B∣)=∣A∣+∣B∣\max(|A \cup B|) = |A| + |B|
Case 4: Finding Minimum Value of |A ∪ B|
The minimum value of |A ∪ B| occurs when one set is completely inside the other.
min(∣A∪B∣)=max(∣A∣,∣B∣)\min(|A \cup B|) = \max(|A|, |B|)
3. Shortcut Example Question
Question:
If |A| = 10 and |B| = 7, then what is the maximum and minimum value of |A ∩ B|?
Solution:
Maximum: When B is completely inside A,
max(∣A∩B∣)=min(10,7)=7\max(|A \cap B|) = \min(10, 7) = 7
Minimum: When A and B are disjoint,
min(∣A∩B∣)=0\min(|A \cap B|) = 0
Final Answer: Maximum = 7, Minimum = 0
4. Short Tricks to Remember
For Intersection (A ∩ B):
- Max = Smaller Set Size
- Min = 0 (if disjoint)
For Union (A ∪ B):
- Max = Sum of Both Set Sizes
- Min = Larger Set Size
Conclusion
These short tricks help solve Set Theory Maxima-Minima problems quickly in GATE, SSC, and other competitive exams. Would you like me to add more practice questions with solutions?