Short trick method for solving propositions argument based problem of discrete mathematics-GATE 2025.
Short trick method for solving propositions argument based problem of discrete mathematics-GATE 2025.
Here’s a short-trick method for solving Propositions/Argument-Based Problems in Discrete Mathematics – highly useful for GATE 2025 CSE/IT aspirants.
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Topic: Propositional Logic (Argument Validity) – Shortcut Method
What is the Goal?
You are often asked:
“Is this argument valid?”
Or
“Which conclusion logically follows from the given premises?”
Instead of using truth tables (which are time-consuming), use this shortcut method:
TRICK: Use the “Assume True Premises, Test False Conclusion” Method
Step-by-Step:
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Assume all premises are TRUE
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Assume the conclusion is FALSE
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Try to find a truth assignment (T/F for each variable) that satisfies both.
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If you can, argument is invalid.
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If you cannot, argument is valid.
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Example Question (GATE Style):
Given:
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Premise 1: p → q
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Premise 2: q → r
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Conclusion: p → r
Is the argument valid?
Apply the Trick:
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Assume premises are true:
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p → q is true
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q → r is true
-
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Assume conclusion is false:
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p → r is false ⟹ p = T, r = F
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Now check:
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p = T
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r = F
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For p → q to be true and p = T, then q = T
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For q → r to be true and q = T, then r = T
(but we assumed r = F)
Contradiction. So no such assignment exists.
Conclusion: Argument is Valid
Bonus Shortcut Symbols to Remember
Symbol | Meaning |
---|---|
∧ | AND |
∨ | OR |
→ | IMPLIES |
↔ | BICONDITIONAL (IFF) |
¬ | NOT (Negation) |
Truth Value Hints (for implication p → q
)
p | q | p → q |
---|---|---|
T | T | T |
T | F | F |
F | T | T |
F | F | T |
Only false when p = T and q = F
Fast Tips:
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Conjunction (p ∧ q) is false if any one is false
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Disjunction (p ∨ q) is true if any one is true
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Implication (p → q) is only false when p = T and q = F
Practice It:
Try this:
Premises:
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¬p ∨ q
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¬q ∨ r
Conclusion:
¬p ∨ r
Try using the same trick and you’ll quickly conclude: the argument is valid.
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