Short trick method for solving propositions argument based problem of discrete mathematics-GATE 2025.

Short trick method for solving propositions argument based problem of discrete mathematics-GATE 2025.



play-rounded-fill play-rounded-outline play-sharp-fill play-sharp-outline
pause-sharp-outline pause-sharp-fill pause-rounded-outline pause-rounded-fill
00:00

Here’s a short-trick method for solving Propositions/Argument-Based Problems in Discrete Mathematics – highly useful for GATE 2025 CSE/IT aspirants.


Contents [hide]

🧠 Topic: Propositional Logic (Argument Validity) – Shortcut Method

🎯 What is the Goal?

You are often asked:

“Is this argument valid?”
Or
“Which conclusion logically follows from the given premises?”

Instead of using truth tables (which are time-consuming), use this shortcut method:


🔍 TRICK: Use the “Assume True Premises, Test False Conclusion” Method

✅ Step-by-Step:

  1. Assume all premises are TRUE

  2. Assume the conclusion is FALSE

  3. Try to find a truth assignment (T/F for each variable) that satisfies both.

    • If you can, argument is invalid.

    • If you cannot, argument is valid.


📘 Example Question (GATE Style):

Given:

  • Premise 1: p → q

  • Premise 2: q → r

  • Conclusion: p → r

Is the argument valid?


🔍 Apply the Trick:

  1. Assume premises are true:

    • p → q is true

    • q → r is true

  2. Assume conclusion is false:

    • p → r is false ⟹ p = T, r = F

Now check:

  • p = T

  • r = F

  • For p → q to be true and p = T, then q = T

  • For q → r to be true and q = T, then r = T ❌ (but we assumed r = F)

❌ Contradiction. So no such assignment exists.

✅ Conclusion: Argument is Valid


⚡ Bonus Shortcut Symbols to Remember

Symbol Meaning
AND
OR
IMPLIES
BICONDITIONAL (IFF)
¬ NOT (Negation)

✨ Truth Value Hints (for implication p → q)

p q p → q
T T T
T F F
F T T
F F T

Only false when p = T and q = F


📌 Fast Tips:

  • Conjunction (p ∧ q) is false if any one is false

  • Disjunction (p ∨ q) is true if any one is true

  • Implication (p → q) is only false when p = T and q = F


🧪 Practice It:

👉 Try this:

Premises:

  1. ¬p ∨ q

  2. ¬q ∨ r

Conclusion:
¬p ∨ r

Try using the same trick and you’ll quickly conclude: the argument is valid.


Would you like a PDF notes version, practice problems, or a video explanation with examples for this topic?

Short trick method for solving propositions argument based problem of discrete mathematics-GATE 2025.

Notes on Discrete Mathematics

Discrete Mathematics and Its Applications, Eighth Edition



Leave a Reply

Your email address will not be published. Required fields are marked *

error: