H.C. Verma's "Concepts of Physics" is a popular book for understanding physics concepts, especially for students preparing for competitive exams like JEE and NEET. It is divided into two volumes:
- Volume 1: Covers Mechanics, Waves, and Thermodynamics.
- Volume 2: Covers Electromagnetism, Optics, and Modern Physics.
If you're looking for solutions to the problems from the book, I can help explain step-by-step solutions or guide you through specific questions.
Would you like a solution for a particular problem or a chapter-wise explanation?
Contents
Solution of Concept of Physics Hc Verma
Concepts of Physics by H.C. Verma is one of the most recommended books for physics preparation in India, especially for IIT-JEE, NEET, and other competitive exams. If you're looking for solutions to the problems in H.C. Verma, hereβs how I can help:

Available Support for H.C. Verma Solutions

Book Structure:
Volume 1: Mechanics, Waves, Thermodynamics
Volume 2: Electrodynamics, Optics, Modern Physics

Chapters Covered (Examples):
Volume 1
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Introduction to Physics
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Motion in One Dimension
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Laws of Motion
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Work and Energy
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Rotational Mechanics
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Gravitation
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Simple Harmonic Motion
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Fluid Mechanics
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Heat and Thermodynamics
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Kinetic Theory of Gases
Volume 2
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Electrostatics
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Current Electricity
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Magnetic Effects of Current
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Electromagnetic Induction
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Alternating Current
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Ray Optics
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Wave Optics
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Modern Physics
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Semiconductors
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Communication Systems

What I Can Provide:
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Detailed step-by-step solutions to any question from any chapter -
Concept explanation behind the questions -
Diagrams and formula derivations -
MCQ and subjective questions discussion -
Hints for difficult problems -
Solutions in Hindi or English β as per your preference

Example:
Chapter: Laws of Motion β Q.5 (HCV Vol 1)
Question:
A block of mass 5 kg is placed on a smooth horizontal table and is tied to a string which passes over a pulley and hangs a 2 kg mass. Find the acceleration and tension.
Solution:
Let:
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m1=5βkgm_1 = 5 \, \text{kg}m1β=5kg (on table)
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m2=2βkgm_2 = 2 \, \text{kg}m2β=2kg (hanging)
Apply Newtonβs laws:
a=m2β gm1+m2=2β 9.85+2=19.67=2.8βm/s2a = \frac{m_2 \cdot g}{m_1 + m_2} = \frac{2 \cdot 9.8}{5 + 2} = \frac{19.6}{7} = 2.8 \, \text{m/s}^2a=m1β+m2βm2ββ gβ=5+22β 9.8β=719.6β=2.8m/s2 T=m1β a=5β 2.8=14βNT = m_1 \cdot a = 5 \cdot 2.8 = 14 \, \text{N}T=m1ββ a=5β 2.8=14N
Acceleration = 2.8 m/sΒ², Tension = 14 N

How Would You Like the Solutions?
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