Solution of Concept of Physics Hc Verma

H.C. Verma's "Concepts of Physics" is a popular book for understanding physics concepts, especially for students preparing for competitive exams like JEE and NEET. It is divided into two volumes:

• Volume 1: Covers Mechanics, Waves, and Thermodynamics.
• Volume 2: Covers Electromagnetism, Optics, and Modern Physics.

If you're looking for solutions to the problems from the book, I can help explain step-by-step solutions or guide you through specific questions.

Would you like a solution for a particular problem or a chapter-wise explanation?

Solution of Concept of Physics Hc Verma

Concepts of Physics by H.C. Verma is one of the most recommended books for physics preparation in India, especially for IIT-JEE, NEET, and other competitive exams. If you're looking for solutions to the problems in H.C. Verma, here’s how I can help:

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Available Support for H.C. Verma Solutions

Book Structure:

Volume 1: Mechanics, Waves, Thermodynamics
Volume 2: Electrodynamics, Optics, Modern Physics

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Chapters Covered (Examples):

Volume 1

1. Introduction to Physics

2. Motion in One Dimension

3. Laws of Motion

4. Work and Energy

5. Rotational Mechanics

6. Gravitation

7. Simple Harmonic Motion

8. Fluid Mechanics

9. Heat and Thermodynamics

10. Kinetic Theory of Gases

Volume 2

1. Electrostatics

2. Current Electricity

3. Magnetic Effects of Current

4. Electromagnetic Induction

5. Alternating Current

6. Ray Optics

7. Wave Optics

8. Modern Physics

9. Semiconductors

10. Communication Systems

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What I Can Provide:

• Detailed step-by-step solutions to any question from any chapter

• Concept explanation behind the questions

• Diagrams and formula derivations

• MCQ and subjective questions discussion

• Hints for difficult problems

• Solutions in Hindi or English – as per your preference

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Example:

Chapter: Laws of Motion – Q.5 (HCV Vol 1)

Question:
A block of mass 5 kg is placed on a smooth horizontal table and is tied to a string which passes over a pulley and hangs a 2 kg mass. Find the acceleration and tension.

Solution:

Let:

• m1=5 kgm_1 = 5 \, \text{kg}m1​=5kg (on table)

• m2=2 kgm_2 = 2 \, \text{kg}m2​=2kg (hanging)

Apply Newton’s laws:

a=m2⋅gm1+m2=2⋅9.85+2=19.67=2.8 m/s2a = \frac{m_2 \cdot g}{m_1 + m_2} = \frac{2 \cdot 9.8}{5 + 2} = \frac{19.6}{7} = 2.8 \, \text{m/s}^2a=m1​+m2​m2​⋅g​=5+22⋅9.8​=719.6​=2.8m/s2 T=m1⋅a=5⋅2.8=14 NT = m_1 \cdot a = 5 \cdot 2.8 = 14 \, \text{N}T=m1​⋅a=5⋅2.8=14N

Answer:
Acceleration = 2.8 m/s², Tension = 14 N

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How Would You Like the Solutions?

• Chapter-wise PDF?

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Let me know the chapter and question number, and I’ll send the full solution!