Resonance Chemistry Equivalent Concept & Titrations
Contents [hide]
- 0.1 Resonance in Chemistry & Equivalent Concept in Titrations
- 0.2 Resonance in Chemistry
- 0.3 Equivalent Concept in Titration (Chemistry)
- 0.4 Acid-Base Titration Example:
- 0.5 Redox Titration Example:
- 0.6 Key Takeaways:
- 0.7 Resonance Chemistry Equivalent Concept & Titrations
- 0.8 Some Basic Concepts of Chemistry
- 0.9 CONTENT Download
- 0.10 Redox-Reaction-Notes.pdf
- 1
Resonance Chemistry (Equivalent Concept) & Titrations
- 2
PART 1: Resonance Chemistry – Equivalent Concept
- 3
What is the Equivalent Concept in Chemistry?
- 4
PART 2: Titrations – Volumetric Analysis
- 5
Quick Practice Question:
- 6
Summary Chart
Resonance in Chemistry & Equivalent Concept in Titrations
Resonance in Chemistry
Resonance is a concept in chemistry where a molecule or ion can be represented by two or more Lewis structures, which differ only in the position of electrons but have the same atomic arrangement.
Example: Benzene (C₆H₆)
- Benzene has two equivalent resonance structures, where the double bonds shift positions.
- The actual structure is a hybrid of these resonance forms, making benzene more stable than expected from a single Lewis structure.
Key Points About Resonance:
Delocalization of electrons occurs, increasing stability.
The actual structure is a resonance hybrid, not a flipping between structures.
More resonance structures = More stability (e.g., carbonate ion CO₃²⁻ has three equivalent resonance forms).
Equivalent Concept in Titration (Chemistry)
The Equivalent Concept is crucial in acid-base titrations, redox reactions, and precipitation reactions. It helps in simplifying complex calculations involving molarity, normality, and titration reactions.
1. Equivalent Weight Formula:
Equivalent weight=Molecular weightn-factor\text{Equivalent weight} = \frac{\text{Molecular weight}}{\text{n-factor}}Equivalent weight=n-factorMolecular weight
Where n-factor depends on the type of reaction:
Acid-Base Titration → n-factor = Number of H⁺ or OH⁻ ions exchanged
Redox Reactions → n-factor = Number of electrons exchanged
2. Normality (N) Formula:
Normality=Moles of solute×n-factorVolume of solution in Liters\text{Normality} = \frac{\text{Moles of solute} \times \text{n-factor}}{\text{Volume of solution in Liters}}Normality=Volume of solution in LitersMoles of solute×n-factor
Or
N=M×n(Normality=Molarity×n-factor)N = M \times n \quad (\text{Normality} = \text{Molarity} \times \text{n-factor})N=M×n(Normality=Molarity×n-factor)
Acid-Base Titration Example:
In the reaction:
H₂SO₄+2NaOH→Na₂SO₄+2H₂O\text{H₂SO₄} + 2 \text{NaOH} → \text{Na₂SO₄} + 2 \text{H₂O}H₂SO₄+2NaOH→Na₂SO₄+2H₂O
H₂SO₄ (Sulfuric Acid) has n-factor = 2 (it gives 2 H⁺ ions).
NaOH has n-factor = 1 (it gives 1 OH⁻ ion).
Using the Normality Equation:
N1V1=N2V2N_1V_1 = N_2V_2N1V1=N2V2
Where:
- N1,V1N_1, V_1N1,V1 = Normality & Volume of Acid
- N2,V2N_2, V_2N2,V2 = Normality & Volume of Base
This helps in finding unknown concentrations in titrations.
Redox Titration Example:
For the reaction:
KMnO₄+5Fe²⁺+8H⁺→Mn²⁺+5Fe³⁺+4H₂O\text{KMnO₄} + 5 \text{Fe²⁺} + 8 \text{H⁺} → \text{Mn²⁺} + 5 \text{Fe³⁺} + 4 \text{H₂O}KMnO₄+5Fe²⁺+8H⁺→Mn²⁺+5Fe³⁺+4H₂O
KMnO₄ (Potassium Permanganate) has n-factor = 5 (Mn⁷⁺ → Mn²⁺, gaining 5 electrons).
Fe²⁺ to Fe³⁺ has n-factor = 1 (losing 1 electron).
Here, we apply:
N1V1=N2V2N_1V_1 = N_2V_2N1V1=N2V2
to determine the concentration of Fe²⁺ solution.
Key Takeaways:
Resonance increases stability by electron delocalization.
Equivalent weight = Molecular weight / n-factor.
Normality (N) = Molarity (M) × n-factor.
Titration formula: N1V1=N2V2N_1V_1 = N_2V_2N1V1=N2V2 helps find unknown concentrations.
Let me know if you need more examples!
Resonance Chemistry Equivalent Concept & Titrations
Some Basic Concepts of Chemistry
CONTENT Download
Redox-Reaction-Notes.pdf
Here is a student-friendly guide on two important topics from Chemistry:
Resonance Chemistry (Equivalent Concept) & Titrations
For: Class 11–12, NEET, JEE, and Competitive Exams
PART 1: Resonance Chemistry – Equivalent Concept
What is Resonance?
- Resonance is a way to describe molecules where one structure is not enough to explain the bonding.
- In such cases, multiple structures (called resonance structures) are written, and the actual structure is a hybrid of all.
Example: Benzene (C₆H₆)
- Benzene has alternating double and single bonds.
- Two main structures (Kekulé structures) exist:
Structure 1 Structure 2
C=C–C=C–C=C ⇄ C–C=C–C=C–C
- The real structure is a resonance hybrid with equal bond lengths between all carbon atoms.
Resonance Rules:
- Only π electrons and lone pairs move.
- σ bonds (single bonds) never move.
- All resonance structures must be valid Lewis structures.
- The hybrid is more stable than individual contributors.
What is the Equivalent Concept in Chemistry?
The Equivalent Concept is used in acid-base and redox reactions and titrations to relate substances based on the amount that reacts.
Equivalent =
The amount of a substance that reacts with or supplies 1 mole of H⁺ ions (acid)
or OH⁻ ions (base) or 1 mole of electrons (in redox reactions).
Equivalent Mass Formulae
Substance Type | Formula |
---|---|
Acid | Molar Mass / Basicity |
Base | Molar Mass / Acidity |
Salt | Molar Mass / Total positive or negative charge |
Oxidizing/Reducing Agent | Molar Mass / n-factor |
PART 2: Titrations – Volumetric Analysis
What is Titration?
Titration is a laboratory method to determine the unknown concentration of a solution by reacting it with a known volume/concentration of another solution.
Basic Formula:
N₁V₁ = N₂V₂
Where:
- N₁, V₁ = Normality & Volume of Solution 1
- N₂, V₂ = Normality & Volume of Solution 2
You can also use:
M₁V₁ / n₁ = M₂V₂ / n₂
Where:
- M = Molarity
- n = Number of H⁺ or OH⁻ or electrons exchanged
Types of Titrations:
Type | Example | Indicator |
---|---|---|
Acid–Base | HCl vs NaOH | Phenolphthalein |
Redox | KMnO₄ vs FeSO₄ | Self-indicator |
Complexometric | EDTA vs Metal ions (Ca²⁺, Mg²⁺) | Eriochrome Black T |
Precipitation | AgNO₃ vs NaCl | Potassium chromate |
Indicators Summary:
Indicator | Color in Acid | Color in Base |
---|---|---|
Phenolphthalein | Colorless | Pink |
Methyl Orange | Red | Yellow |
Quick Practice Question:
Q: 20 mL of 0.1 N HCl is completely neutralized by 25 mL of NaOH. Find the Normality of NaOH.
A:
Use N₁V₁ = N₂V₂
→ (0.1)(20) = N₂(25)
→ N₂ = 2 / 25 = 0.08 N
Summary Chart
Topic | Key Formula / Idea |
---|---|
Resonance | Real molecule = Resonance Hybrid |
Equivalent Mass | Molar Mass / n-factor |
Acid-Base Titration | N₁V₁ = N₂V₂ or M₁V₁/n₁ = M₂V₂/n₂ |
Redox Reaction | e⁻ transferred determines n-factor |
Would you like a PDF with diagrams, solved numericals, and a quiz on this topic? Let me know your class or exam target (NEET/JEE/CBSE), and I’ll create a tailored study note!