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Computer Science/Numerical Methods/ Iteration method ( with it’s convergence condition).

Computer Science/Numerical Methods/ Iteration method ( with it’s convergence condition).

https://www.gyanodhan.com/video/7A2.%20Computer%20Science/Numerical%20Methods/673.%20Iteration%20method%20%20%28%20with%20it%27s%20convergence%20condition%29.mp4

Iteration Method in Numerical Methods

The Iteration Method is a technique used to find the root of an equation f(x)=0f(x) = 0. It is based on approximating the root through successive iterations, refining the value until it reaches the desired accuracy.

1. General Form of Iteration Method

The given equation f(x)=0f(x) = 0 is rewritten in the form:

x=g(x)x = g(x)

where g(x)g(x) is a function derived from f(x)f(x).

An initial guess x0x_0 is selected, and the next approximation is obtained using the formula:

xn+1=g(xn)x_{n+1} = g(x_n)

This process continues until the absolute difference between successive approximations is less than a predefined tolerance ϵ\epsilon, i.e.,

∣xn+1−xn∣<ϵ|x_{n+1} – x_n| < \epsilon

2. Convergence Condition

For the iteration method to converge to a root α\alpha, the function g(x)g(x) must satisfy:

∣g′(α)∣<1| g'(\alpha) | < 1

where g′(α)g'(\alpha) is the derivative of g(x)g(x) evaluated at the root α\alpha.

Explanation of Convergence Condition

3. Example of Iteration Method

Find the root of x3+x−1=0x^3 + x – 1 = 0 using iteration method.

Step 1: Rewrite in the form x=g(x)x = g(x)

x=1−x3x = 1 – x^3

Step 2: Select an initial guess

Let x0=0.5x_0 = 0.5.

Step 3: Apply the iteration formula

Using xn+1=1−xn3x_{n+1} = 1 – x_n^3,

x1=1−(0.5)3=1−0.125=0.875x_1 = 1 – (0.5)^3 = 1 – 0.125 = 0.875 x2=1−(0.875)3=1−0.6699=0.3301x_2 = 1 – (0.875)^3 = 1 – 0.6699 = 0.3301 x3=1−(0.3301)3=1−0.0359=0.9641x_3 = 1 – (0.3301)^3 = 1 – 0.0359 = 0.9641

This process continues until convergence.

4. Advantages and Disadvantages

Advantages:

Disadvantages:

If you need more examples or explanations, let me know!

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