Day 04Part 15(B) – Discrete Mathematics – Methods of solving Statements and boolean expressions.
Day 04Part 15(B) – Discrete Mathematics – Methods of solving Statements and boolean expressions.
Contents [hide]
- 0.0.1 Discrete Mathematics – Methods of Solving Statements and Boolean Expressions
- 0.0.2 1. Logical Statements and Boolean Expressions
- 0.0.3 Boolean Variables & Operations
- 0.0.4 2. Methods of Solving Logical Statements
- 0.0.5 A. Truth Table Method
- 0.0.6 B. Algebraic Simplification (Boolean Algebra)
- 0.0.7 C. Karnaugh Map (K-Map) Method
- 0.0.8 3. Practical Applications
- 0.0.9 Day 04Part 15(B) – Discrete Mathematics – Methods of solving Statements and boolean expressions.
- 0.0.10 DIGITAL NOTES ON Discrete Mathematics B.TECH II YEAR
- 0.0.11 Discrete Mathematics for Computer Science
- 0.0.12 dmoi-tablet.pdf – Discrete Mathematics
- 0.0.13 Notes on Discrete Mathematics
- 0.0.14 DISCRETE MATHEMATICS
- 1
Day 04 Part 15(B) – Discrete Mathematics
Discrete Mathematics – Methods of Solving Statements and Boolean Expressions
In Discrete Mathematics, logical statements and Boolean expressions are fundamental concepts used in propositional logic, set theory, and digital logic design. Let’s explore different methods to solve them.
1. Logical Statements and Boolean Expressions
A statement (proposition) is a sentence that is either true (T) or false (F) but not both.
Boolean Variables & Operations
Boolean expressions use logical operators:
- AND ( ∧ ) → True if both inputs are true.
- OR ( ∨ ) → True if at least one input is true.
- NOT ( ¬ ) → Reverses the truth value.
- IMPLICATION ( → ) → If P → Q, Q must be true when P is true.
- BICONDITIONAL ( ↔ ) → True if both sides have the same truth value.
2. Methods of Solving Logical Statements
A. Truth Table Method
A truth table evaluates all possible truth values for a Boolean expression.
Example: Solve (P ∨ Q) → R
P | Q | R | P ∨ Q | (P ∨ Q) → R |
---|---|---|---|---|
T | T | T | T | T |
T | T | F | T | F |
T | F | T | T | T |
T | F | F | T | F |
F | T | T | T | T |
F | T | F | T | F |
F | F | T | F | T |
F | F | F | F | T |
Result: The expression is not a tautology (it is false in some cases).
B. Algebraic Simplification (Boolean Algebra)
Using Boolean algebra rules, expressions can be simplified.
Example: Simplify A + A’B
Solution:
- Apply Absorption Law:
A + A’B = (A + B)
Example: Simplify (A + B)(A + C)
Solution:
- Apply Distribution Law:
(A + B)(A + C) = A + BC
C. Karnaugh Map (K-Map) Method
Used for minimizing Boolean expressions, especially in digital logic.
Example: Simplify F(A, B, C) = Σ(1, 3, 4, 6, 7) using a K-map.
- Draw a 3-variable K-map.
- Group 1s into power-of-two blocks.
- Derive the simplified equation.
3. Practical Applications
Digital Circuit Design – Simplifying Boolean expressions reduces hardware cost.
Computer Programming – Used in conditional statements and algorithms.
Mathematical Logic – Helps in theorem proving and automated reasoning.
Would you like more examples or a step-by-step K-map solution?
Day 04Part 15(B) – Discrete Mathematics – Methods of solving Statements and boolean expressions.
DIGITAL NOTES ON Discrete Mathematics B.TECH II YEAR
Discrete Mathematics for Computer Science
dmoi-tablet.pdf – Discrete Mathematics
Notes on Discrete Mathematics
DISCRETE MATHEMATICS
Here’s a structured lesson for:
Day 04 Part 15(B) – Discrete Mathematics
Methods of Solving Statements and Boolean Expressions
PART A: Solving Logical Statements
1. Basic Logical Connectives
Symbol | Meaning | Example |
---|---|---|
¬P | NOT P | If P = true, then ¬P = false |
P ∧ Q | P AND Q | True only if both are true |
P ∨ Q | P OR Q | True if at least one is true |
P → Q | Implication | “If P then Q” |
P ↔ Q | Biconditional | True when P and Q have same truth value |
2. Truth Table Method
Example:
Statement: P→QP \rightarrow Q
P | Q | P → Q |
---|---|---|
T | T | T |
T | F | F |
F | T | T |
F | F | T |
Use this to prove tautology, contradiction, contingency.
3. Logical Equivalence
Use laws to simplify:
Law | Example |
---|---|
De Morgan’s Laws | ¬(P ∧ Q) ≡ ¬P ∨ ¬Q |
Double Negation | ¬(¬P) ≡ P |
Implication | P → Q ≡ ¬P ∨ Q |
Contrapositive | P → Q ≡ ¬Q → ¬P |
Distributive Law | P ∧ (Q ∨ R) ≡ (P ∧ Q) ∨ (P ∧ R) |
PART B: Solving Boolean Expressions
1. Boolean Algebra Basics
Operation | Symbol | Rule |
---|---|---|
AND | · | A · B |
OR | + | A + B |
NOT | ¬ or ′ | ¬A or A′ |
2. Boolean Laws
Law | Expression |
---|---|
Identity | A + 0 = A, A · 1 = A |
Null | A + 1 = 1, A · 0 = 0 |
Idempotent | A + A = A, A · A = A |
Complement | A + A′ = 1, A · A′ = 0 |
Double Negation | (A′)′ = A |
3. Simplifying Boolean Expressions
Example:
Expression:
A + A·B
Apply Absorption Law:
A + A·B = A
Another:
Expression:
A·B + A·B′
Apply Distributive Law:
A·(B + B′) = A·1 = A
Practice Problem Set
- Prove using truth tables:
- (P∧Q)→P(P ∧ Q) → P is a tautology.
- Simplify Boolean expression:
- A⋅(B+A′)A·(B + A′)
- Check if:
- P∨(¬P∧Q)≡P∨QP ∨ (¬P ∧ Q) ≡ P ∨ Q
Quick Tips
- Use truth tables for 2–3 variable expressions.
- Use Boolean algebra rules to reduce expressions in logic circuits.
- Always look to factor, distribute, or absorb to simplify.
Would you like:
- A PDF of Boolean Laws Cheat Sheet?
- Truth Table Generator (Python or Excel)?
- Or Practice Quiz with Solutions?
Let me know!